Re: Small question about performance

From:	Stas Malyshev	Date:	Thu, 15 Mar 2012 16:49:45 +0000
Subject:	Re: Small question about performance
References:	1 2	Groups:	php.internals
Request:	Send a blank email to internals+get-58964@lists.php.net to get a copy of this message

Hi!

If I am understanding the text correctly it is saying that
     $f1 = f1();
     $f2 = f2($f1);
     $f3 = f3($f2);
is using more memory than
     $f3 = f3(f2(f1()));

Short answer: it doesn't matter, use either as you wish. Long answer: Technically, the former also uses hash buckets to bind values to the symbol table, so it can use more memory (and if it so happens that using these variables makes symbol table go over hashtable threshold, hashtable internal storage size will be increased), so it will consume marginally more memory. But the difference is completely negligible. -- Stanislav Malyshev, Software Architect SugarCRM: http://www.sugarcrm.com/ (408)454-6900 ext. 227