Re: [RFC] Property Accessors v1.2 : isset / unset "failable"
| From: | Clint Priest | Date: | Sun, 06 Jan 2013 18:13:01 +0000 |
| Subject: | Re: [RFC] Property Accessors v1.2 : isset / unset "failable" | ||
| References: | 1 2 3 4 5 6 7 | Groups: | php.internals |
| Request: | Send a blank email to internals+get-64607@lists.php.net to get a copy of this message | ||
Bringing up this old issue a bit.
Nothing was ever said of unset? Should unset be benign?
Since unset() is intended to take an action (rather than check on state) shouldn't an invalid unset (one with a guarded property that doesn't have a setter) emit a warning?
On 10/30/2012 10:37 PM, Clint Priest wrote:
Would you say the same of unset? Always benign? On 10/29/2012 2:14 PM, Stas Malyshev wrote:-- -ClintHi!So... to be explicit here, you think in this situation: class a {isset should return false, since $b is not set value. It should not produce any warning. Of course (int) would produce 0 then ;)public $b { set($x) { $this->b = $x; } }} $o = new a(); if(!isset($o->b)) {/* delete files */} echo (int)isset($o->b); /* This should return false and not emit any sort of warning/notice? */I mean specifically, there is no getter defined, therefore the result if isset is indeterminate and while I can see it not causing executionNo, the result is determinate - it's false. That's the point of isset() in PHP and that's how it is used in existing code.to stop I don't see it being a good idea to not warn the developer that what they've attempted is not correct. Without a getter, isset() is not a legal call (since the value cannot be retrieved).isset() should always be legal. This is the way to check if $o->b is legal.