Re: [RFC] Combined Comparison (Spaceship) Operator

Hi Yasuo, > On 23 Jan 2015, at 00:16, Yasuo Ohgaki <yohgaki@ohgaki.net> wrote: > > Hi all, > > On Fri, Jan 23, 2015 at 7:48 AM, Larry Garfield <larry@garfieldtech.com> > wrote: > >> The examples say nothing about mixing types, though. Eg, what would these >> return: >> >> return 0 <=> "0" >> >> return "" <=> 0 >> >> return 1 <=> [1, 2, 3] >> >> Ignoring object property names and going by the order of the property >> definition seems like asking for trouble, too. >> > > It should be the same as '===', IMO. > Only the same type should return 0. > Object has the same id should return 0. > Arrays would be matter of discussion. Having it be the same as === would be inconsistent with our existing sorting and comparison behaviour, so I don’t think it should be changed. If we made it strict like that, we’d also have to define a strict < and > as well, otherwise we have a problem, because in some cases ($x !== $y && !($x < $y) && !($x > $y)) is TRUE. Thanks. -- Andrea Faulds http://ajf.me/