Re: Translating optional zval ** with zend_parse_parameters() to PHP 7

From: Date: Fri, 25 Nov 2016 12:30:33 +0000
Subject: Re: Translating optional zval ** with zend_parse_parameters() to PHP 7
References: 1 2  Groups: php.internals 
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On 11/25/2016 12:27 AM, Kalle Sommer Nielsen wrote:
Hi Thomas 2016-11-25 4:13 GMT+01:00 Thomas Hruska <thruska@cubiclesoft.com>:
I'm working on updating an extension for PHP 7 compatibility. I have one function that uses an optional zval ** with zend_parse_parameters().
        zval **zprevcount = NULL;
        int count;
        int argc = ZEND_NUM_ARGS();
        if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "|Z",
&zprevcount) == FAILURE) return;
        ...
        if (argc > 0)
        {
                count = (int)PrevCount;
                zval_dtor(*zprevcount);
                ZVAL_LONG(*zprevcount, count);
        }
What's the correct way to translate that into PHP 7?
Since you are working with integers, you can do: zend_long prevcount = 0; if(zend_parse_parameters(ZEND_NUM_ARGS(), "|l", &prevcount) == FAILURE) {
        return;
} if(prevcount) {
      /* ... use prevcount ... */
} Notice that all integers returned from the ZPP is a zend_long, you can see more information about the ZPP in php-src/README.PARAMETER_PARSING_API
Unless I missed something, zend_long is generally defined as a standard int64_t or int32_t type (Zend/zend_long.h). I need to be able to *modify* the original variable that was passed in. I already use "|l" and zend_long elsewhere in the extension. I'm thinking the correct ZPP string is "|z/" but the usage examples in core that I've looked at so far are inconsistent, hence the original question of what's the correct approach? -- Thomas Hruska CubicleSoft President I've got great, time saving software that you will find useful. http://cubiclesoft.com/

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