Re: Let range() return a generator?

There are some way to PHP be flagged before run some function, and understand that you wants to return a Generator instead of array? For instance: new Generator(range(1, 1000)) makes range() work like a generator instead of return an array - it's an alternative to avoid new keywords. Or, maybe, some side implementation like Generator::range(1, 1000), Generator::array_values($array), etc. (Currently, for instance, we can simulate the range() Generator, but not array_values()) 2017-03-17 22:14 GMT-03:00 Sara Golemon <pollita@php.net>: > On Fri, Mar 17, 2017 at 10:46 AM, Sara Golemon <pollita@php.net> wrote: > > On Fri, Mar 17, 2017 at 1:40 AM, Niklas Keller <me@kelunik.com> wrote: > >> Yes, that's a BC break. Instead of changing it, there could be a new > >> function. But as it can be simply built in userland, I don't see much > >> reason to have it in core. > >> > > 100% agreed. This is a 3 line function and doing it in userland means > > you can use it in 5.5 or later. > > > > function range($low, $high) { > > for ($i = $low; $i <= $high; ++$i) { yield $i; } > > } > > > In fact, here: This is how easy that is. > > https://packagist.org/packages/phplang/generator > > -- > PHP Internals - PHP Runtime Development Mailing List > To unsubscribe, visit: http://www.php.net/unsub.php > > -- David Rodrigues