fopen() question
| From: | Scott Rider | Date: | Fri, 28 Feb 2003 19:50:29 +0000 |
| Subject: | fopen() question | ||
| Groups: | php.mirrors | ||
| Request: | Send a blank email to php-mirrors+get-15960@lists.php.net to get a copy of this message | ||
What am I doing wrong? I have tried all of these versions inside a for loop
and only the handcoded text will work in the function fopen().
It seems that fopen("filename","r");
isnt the same as
$temp = "filename";
fopen("$temp","r"); or fopen($temp,"r");
or
$temp = "filepath".formatted($generated#)."filename";
fopen("$temp","r"); or fopen($temp,"r");
but$temp = "filepath".formatted($generated#)."filename";
will print the same as a handcoded peice of text.