note 62819 added to language.operators.type

This will fail: <? if ($moo instanceof "Moo") echo "Goo\n"; ?> and this will not: <? if ($moo instanceof Moo) echo "Goo\n"; ?> and although you cant use a quoted string as the class name to check, you can use a variable like this: <? $moo_class = "Moo"; if ($moo instanceof $moo_class) echo "Goo\n"; ?> so if you want to loop through an array of class names to check an object against, you can do it easily. ---- Server IP: 85.116.0.130 Probable Submitter: 80.177.252.222 ---- X-Spam-Status: No, hits=3.1 required=5.0 tests=DATE_MISSING,FROM_NO_LOWER autolearn=no version=2.64 ---- Manual Page -- http://www.php.net/manual/en/language.operators.type.php Edit -- http://master.php.net/note/edit/62819 Del: integrated -- http://master.php.net/note/delete/62819/integrated Del: useless -- http://master.php.net/note/delete/62819/useless Del: bad code -- http://master.php.net/note/delete/62819/bad+code Del: spam -- http://master.php.net/note/delete/62819/spam Del: non-english -- http://master.php.net/note/delete/62819/non-english Del: in docs -- http://master.php.net/note/delete/62819/in+docs Del: other reasons-- http://master.php.net/note/delete/62819 Reject -- http://master.php.net/note/reject/62819 Search -- http://master.php.net/manage/user-notes.php