note 11459 added to preg_replace

you can't include array with a reference to a captured pattern as a key into the replacement string. for example: preg_replace("/blabl(.*?)blo(.*?)/",$array[$1],$contents); i tried with \\1 , no results. with the \e modifier (blbla.$array[1].blbl) . the solution was using /F modifier , and creating a special function... http://www.php.net/manual/en/function.preg-replace.php