note 40724 deleted from function.preg-replace by tularis

Note Submitter: php at equaliser dot net ---- If you're setting your replacement values elsewhere and your replacement value can contain a dollar sign followed by an integer eg: $replacement = 'Dad's $7 shoes' You'll find that preg_replace() treats this (quite rightly) as callback syntax. So, you might want to do this: $replacement = preg_replace("!" . '\x24' . "!" , '\\\$' , $replacement); To your replacement string first; Putting in an escaped backslash '\\' followed by an escaped dollar sign '\$' where every instance appears.