note 49282 deleted from function.phpversion by derick

From: Date: Fri, 04 Aug 2006 13:19:51 +0000
Subject: note 49282 deleted from function.phpversion by derick
References: 1  Groups: php.notes 
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Note Submitter: ground-pilot at net-pilots.com ---- Difference from bleeding edge server and production server where I couldn't use the phpversion() function. Came up with this to grab it from the command line instead. Note that the 'command line' version result , and 'http server api' version result could be two or more different versions, and not matching each other. So this may return a misleading value for your environment? Be careful if you have updated the web server api and not the command line, or visa-versa. ;) But for me - it works. <?php $PHP_VERSION = get_my_phpver(); echo "PHP_VERSION = $PHP_VERSION<br>"; function get_my_phpver() { // USE : // $PHP_VERSION = get_my_phpver(); // CAVEAT NOTES : // exec() will only return last line // passthru() will always show output, even when you ob_start() the output. // shell_exec() will return ALL lines of output but not forced $my_phpver = trim(substr(shell_exec('php -v'), 3, 6)); // returns "4.3.1" of "PHP 4.3.1 (cgi)..." and removes white spaces return $my_phpver; } ?> Of course this would also do the trick... <?php $PHP_VERSION = trim(substr(shell_exec('php -v'), 3, 6)); echo "PHP_VERSION = $PHP_VERSION<br>"; ?> And as always, there are OTHER method, but this works for me. Hope this helps someone else out as well. :)

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