note 68998 added to language.types.object

In reply to the usort thing, you can access a property of an object dynamically by: <?php $obj = (object)array("Test" => "bar") $var = "Test"; echo $obj->$var; ?> This will output "bar", and do notice I call on ->$var and not just ->var. ---- Server IP: 193.27.201.10 (proxied: 193.27.201.10 1.0 www1.shellkonto.se:3128 (squid/2.5.STABLE4)) Probable Submitter: 80.217.189.168 ---- X-Spam-Status: No, hits=3.1 required=5.0 tests=DATE_MISSING,FROM_NO_LOWER autolearn=no version=2.64 ---- Manual Page -- http://www.php.net/manual/en/language.types.object.php Edit -- https://master.php.net/note/edit/68998 Del: integrated -- https://master.php.net/note/delete/68998/integrated Del: useless -- https://master.php.net/note/delete/68998/useless Del: bad code -- https://master.php.net/note/delete/68998/bad+code Del: spam -- https://master.php.net/note/delete/68998/spam Del: non-english -- https://master.php.net/note/delete/68998/non-english Del: in docs -- https://master.php.net/note/delete/68998/in+docs Del: other reasons-- https://master.php.net/note/delete/68998 Reject -- https://master.php.net/note/reject/68998 Search -- https://master.php.net/manage/user-notes.php