note 69379 rejected from function.in-array by betz

Note Submitter: sabainabukhari at yahoo dot com ---- I didn't find this anywhere in the manual or in the notes. I'm sorry if this is a repetition, but I just found this out the hard way :( If the haystack array contains only ONE element, then in_array will give this warning: Wrong datatype for second argument in call to in_array() This can be fixed by explicitly typecasting the haystack array to an array. <? $haystack = (array) $haystack; if(in_array($needle, $haystack)) return true; else return false; ?>