note 69691 added to function.date

If you have a date in the english format"Thu Sep 07 23:59:35 CEST 2006" (some times generated from logs or other systems) and you need to translate it in mm/dd/yyyy you can use the following function! //$data="Thu Sep 07 23:59:35 CEST 2006"; function formadatedb($data) { $dt=explode(" ", $data); $year=array ("Jan"=>1, "Feb"=>2, "Mar"=>3, "Apr"=>4, "May"=>5, "Jun"=>6, "Jul"=>7, "Aug"=>8, "Sep"=>9,"Oct"=>10,"Nov"=>11,"Dec"=>12); return $year[$dt[1]]."/".$dt[2]."/".$dt[5]; } ---- Server IP: 66.163.161.117 Probable Submitter: 80.78.67.191 ---- Manual Page -- http://www.php.net/manual/en/function.date.php Edit -- https://master.php.net/note/edit/69691 Del: integrated -- https://master.php.net/note/delete/69691/integrated Del: useless -- https://master.php.net/note/delete/69691/useless Del: bad code -- https://master.php.net/note/delete/69691/bad+code Del: spam -- https://master.php.net/note/delete/69691/spam Del: non-english -- https://master.php.net/note/delete/69691/non-english Del: in docs -- https://master.php.net/note/delete/69691/in+docs Del: other reasons-- https://master.php.net/note/delete/69691 Reject -- https://master.php.net/note/reject/69691 Search -- https://master.php.net/manage/user-notes.php