note 69822 added to language.operators.type

instanceof only works with objects. So if you want to check if a variable is an object that implements a certain interface, you need two checks: is_object and instanceof. A fatal error occurs if instanceof is used with other data types. ---- Server IP: 83.137.20.120 Probable Submitter: 213.84.72.157 ---- Manual Page -- http://www.php.net/manual/en/language.operators.type.php Edit -- https://master.php.net/note/edit/69822 Del: integrated -- https://master.php.net/note/delete/69822/integrated Del: useless -- https://master.php.net/note/delete/69822/useless Del: bad code -- https://master.php.net/note/delete/69822/bad+code Del: spam -- https://master.php.net/note/delete/69822/spam Del: non-english -- https://master.php.net/note/delete/69822/non-english Del: in docs -- https://master.php.net/note/delete/69822/in+docs Del: other reasons-- https://master.php.net/note/delete/69822 Reject -- https://master.php.net/note/reject/69822 Search -- https://master.php.net/manage/user-notes.php