note 69901 added to language.references.pass

Actually there is a way to give a default value to a reference argument, if you need it badly. It fires a warning, but you can prefix the function call with an @. Of course, you cannot pass literals by reference. <?php function byref( &$ref ) { if( !isset( $ref ) ) $ref = "default value"; print $ref; // default or given value? who knows! } $hi = "some value "; byref( $hi ); // works fine @byref(); // missing argument warning, but works byref( "hey!" ); // this will raise a fatal error ?> ---- Server IP: 201.216.232.3 Probable Submitter: 200.114.166.165 ---- Manual Page -- http://www.php.net/manual/en/language.references.pass.php Edit -- https://master.php.net/note/edit/69901 Del: integrated -- https://master.php.net/note/delete/69901/integrated Del: useless -- https://master.php.net/note/delete/69901/useless Del: bad code -- https://master.php.net/note/delete/69901/bad+code Del: spam -- https://master.php.net/note/delete/69901/spam Del: non-english -- https://master.php.net/note/delete/69901/non-english Del: in docs -- https://master.php.net/note/delete/69901/in+docs Del: other reasons-- https://master.php.net/note/delete/69901 Reject -- https://master.php.net/note/reject/69901 Search -- https://master.php.net/manage/user-notes.php