note 70339 deleted from function.preg-replace by colder

Note Submitter: elaineseery at hotmail dot com Reason: in docs ---- another note for newcomers to this function! you can use variables instead of absolute text when building your input text. however, this won't work: $input = "your name" . $_GET['name']; $in[0] = '/$input/'; $out[0] = "greetings friend!"; $new_contents = preg_replace($in, $out, $contents); - because the $input is interpreted literally, instead of being expanded. this will work (note the double quotes around $in[0]) $input = "your name " . $_GET['name']; $in[0] = "/$input/"; $out[0] = "greetings friend!"; $new_contents = preg_replace($in, $out, $contents); one more point, if you're using a / in your $input, you'll need to escape it e.g. if you have $input = "mysite/stuff/" . $_POST['filename']; you'll need to change it to $input = "mysite\/stuff\/" . $_POST['filename']; note: this is a very simple example, it probably wouldn't take much to break it and note note: there's a useful tutorial at http://www.tote-taste.de/X-Project/regex/printable.html