note 54039 deleted from language.types.string by colder

Note Submitter: diannes at dbfields dot com ---- I was trying to perform a series of manipulations on a string and found that there doesn't seem to be any easy way to force variable expansion to occur if a string hadn't originally been created as double-quoted or heredoc. Maybe there's an easier workaround than the one below, but it's what I ended up doing. ------------------------------- $var = '5'; $str = "var = $var "; echo $str; // prints 'var = "5" ' (expected result) $str = 'var = "$var" '; echo $str; // prints 'var = "$var" ' (expected result) // NO VARIABLE EXPANSION: $str = 'var = "$var" '; echo $str; // prints 'var = "$var" ' echo "$str"; // prints 'var = "$var" ' $str = "$str"; echo $str; // still prints 'var = "$var" ' $str = (string)$str; echo $str; // still prints 'var = "$var" ' $str = strval($str); echo $str; // still prints 'var = "$var" ' // NO VARIABLE EXPANSION THIS WAY EITHER: $str = 'var = "{$var}" '; // yields similar results to above // NO VARIABLE EXPANSION WHEN STRING IS FROM A FILE $str = implode("",file("foo")); echo $str; // prints 'var = "$var" ' // THIS WILL FORCE VARIABLE EXPANSION TO OCCUR: $str = str_replace('"','\"',$str); // escape double quotes echo eval('echo "'.$str.'";'); // prints 'var = "5" ' $str = 'ob_start(); echo "'.$str.'"; ob_get_contents();'; $str = eval($str); echo $str; // prints 'var = "5" '