note 71544 added to function.is-dir

I find the following method for testing if the folder's contents are themselves folders. Like alan rezende said, "the function is_dir will always return false if the handle acquired with opendir is not from the current working directory". This solution gets around this by prepending the path to the item being tested (the line with * at the end). <?php $dir = "Folder"; if ($dh = opendir($dir)) { // List all files and folders while ( ($file = readdir($dh)) != false ) { // Neat way to accurately check for a subfolder.... if ( is_dir("$dir/$file") && $file != "." && $file != "..") { //* echo ( "Found a subfolder: " . $file ); } else { echo ( "Found a file: " . $file ); } } } ?> ---- Server IP: 216.235.15.211 Probable Submitter: 205.206.184.159 ---- Manual Page -- http://www.php.net/manual/en/function.is-dir.php Edit -- https://master.php.net/note/edit/71544 Del: integrated -- https://master.php.net/note/delete/71544/integrated Del: useless -- https://master.php.net/note/delete/71544/useless Del: bad code -- https://master.php.net/note/delete/71544/bad+code Del: spam -- https://master.php.net/note/delete/71544/spam Del: non-english -- https://master.php.net/note/delete/71544/non-english Del: in docs -- https://master.php.net/note/delete/71544/in+docs Del: other reasons-- https://master.php.net/note/delete/71544 Reject -- https://master.php.net/note/reject/71544 Search -- https://master.php.net/manage/user-notes.php