note 72199 added to language.operators.comparison

Note that typecasting will NOT prevent the default behavior for converting two numeric strings to numbers when comparing them. e.g.: if ((string) '0123' == (string) '123') print 'equals'; else print 'doesn\'t equal'; Still prints 'equals' As far as I can tell the only way to avoid this is to use the identity comparison operators (=== and !==). ---- Server IP: 64.71.164.2 Probable Submitter: 68.163.130.212 ---- Manual Page -- http://www.php.net/manual/en/language.operators.comparison.php Edit -- https://master.php.net/note/edit/72199 Del: integrated -- https://master.php.net/note/delete/72199/integrated Del: useless -- https://master.php.net/note/delete/72199/useless Del: bad code -- https://master.php.net/note/delete/72199/bad+code Del: spam -- https://master.php.net/note/delete/72199/spam Del: non-english -- https://master.php.net/note/delete/72199/non-english Del: in docs -- https://master.php.net/note/delete/72199/in+docs Del: other reasons-- https://master.php.net/note/delete/72199 Reject -- https://master.php.net/note/reject/72199 Search -- https://master.php.net/manage/user-notes.php