note 75713 added to function.preg-replace

For the benefit of perl coders, $s =~ s/PATTERN/REPLACEMENT/g; becomes: <? $s = preg_replace('/PATTERN/', 'REPLACEMENT', $s); ?> Note that you have to assign the result back to $s. If your preg_replace doesn't seem to be working, you may have merely forgotten to assign the return to $s. ---- Server IP: 69.39.81.135 Probable Submitter: 69.232.64.135 ---- Manual Page -- http://www.php.net/manual/en/function.preg-replace.php Edit -- https://master.php.net/note/edit/75713 Del: integrated -- https://master.php.net/note/delete/75713/integrated Del: useless -- https://master.php.net/note/delete/75713/useless Del: bad code -- https://master.php.net/note/delete/75713/bad+code Del: spam -- https://master.php.net/note/delete/75713/spam Del: non-english -- https://master.php.net/note/delete/75713/non-english Del: in docs -- https://master.php.net/note/delete/75713/in+docs Del: other reasons-- https://master.php.net/note/delete/75713 Reject -- https://master.php.net/note/reject/75713 Search -- https://master.php.net/manage/user-notes.php