note 70833 deleted from function.preg-replace by colder

From: Date: Mon, 18 Jun 2007 20:05:31 +0000
Subject: note 70833 deleted from function.preg-replace by colder
References: 1  Groups: php.notes 
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Note Submitter: bwooster47 at gmail dot com ---- Tripped over a subtle issue in preg_replace! Eventually got the right answers from the readers at alt.comp.lang.php! preg_replace assumes a /g - replace all occurences. So, when you need a replacement to force a single / character at end of string, i.e, replace 0 or more / characters with single /, here's what you need: $t = preg_replace('!/*$!', '/', $s, 1); Note the all important 1 (limit) at the end. Default is -1, and it seems to force a non-greedy match for /*$ , so if $s == aa//, the output is still a// with limit -1. But with 1 as the limit, all values of $s such as aa or aa/ or aa// or aa//// all end up like aa/, just as needed. [Not sure why a//// ends up as a// with limit -1...] So, final story, to make *$ be greedy, use the limit of 1.

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