note 51713 deleted from function.strtotime by derick

Note Submitter: Greg Robbins ---- This function will count fractional months between 2 dates, perhaps for billing purposes (like for hosting, as was my case). <?php function count_months($start_date, $end_date) { //Initialize counters for days and months $days = 0; $months = 0; //get current month (as of your start_date) $curr_month = date("Y-m-01", $start_date); //loop by days while($start_date <= $end_date) { //If the current iteration has passed on to a new month if($curr_month != date("Y-m-01", $start_date)) { //divide the number of days counted by the number of days in the month //to get a decimal representation of how many months should be counted. //Increment the months count by this value $months += $days / date("t", strtotime($curr_month)); //Uncomment the following line to see how it counts month by month //echo "$days Days / " . date("t", strtotime($curr_month)) . " days in month $curr_month<br>\n"; //Advance the current month $curr_month = date("Y-m-01", strtotime($curr_month . " + 1 months")); //Reset the days counter sibce we are now counting a new month $days = 0; } //Advance tot he next day... $start_date = strtotime(date("Y-m-d", $start_date) . " + 1 days"); //And increment the day counter $days++; } //This is the same as above but applied to the last month $months += $days / date("t", strtotime($curr_month)); //Uncomment the following line to see how it counts month by month //echo "$days Days / " . date("t", strtotime($curr_month)) . " days in month $curr_month<br>\n"; //This returns a decimal value to two decimals of accuracy return sprintf("%01.2f", $months); } //Check it out: $last_billed_date = "2004-12-31"; $bill_thru_this_date = "2005-04-15"; $unix_start_date = strtotime($last_billed_date . " +1 days"); $unix_end_date = strtotime($bill_thru_this_date); echo "Last billed date: " . $last_billed_date . "<br>"; echo "Bill through date: " . $bill_thru_this_date . "<br>"; echo "Total months: " . count_months($unix_start_date, $unix_end_date); ?>