note 81140 added to language.variables

@cgorbit: This does not work, because "=" has a lower operator precedence than "||". The expression "($var = $old || true)" assigns true to $var. I corrected this and further shortened the function by putting "$old = $var" into the expression, too. :) Note the parentheses that are necessary because of the operator precedence of "=" and "&&". function var_name(&$var, $scope=0) { if (($old = $var) && ($key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && (($var = $old) || true)) return $key; } ---- Server IP: 69.147.83.197 Probable Submitter: 195.250.48.253 ---- Manual Page -- http://www.php.net/manual/en/language.variables.php Edit -- https://master.php.net/note/edit/81140 Del: integrated -- https://master.php.net/note/delete/81140/integrated Del: useless -- https://master.php.net/note/delete/81140/useless Del: bad code -- https://master.php.net/note/delete/81140/bad+code Del: spam -- https://master.php.net/note/delete/81140/spam Del: non-english -- https://master.php.net/note/delete/81140/non-english Del: in docs -- https://master.php.net/note/delete/81140/in+docs Del: other reasons-- https://master.php.net/note/delete/81140 Reject -- https://master.php.net/note/reject/81140 Search -- https://master.php.net/manage/user-notes.php