note 83776 added to function.eval

You can use eval() to create variable classes. <?php // Works eval("\$myClass = new $className();"); // Doesn't work $myClass = new $className(); ?> ---- Server IP: 208.69.120.35 Probable Submitter: 68.9.241.249 ---- Manual Page -- http://www.php.net/manual/en/function.eval.php Edit -- https://master.php.net/note/edit/83776 Del: integrated -- https://master.php.net/note/delete/83776/integrated Del: useless -- https://master.php.net/note/delete/83776/useless Del: bad code -- https://master.php.net/note/delete/83776/bad+code Del: spam -- https://master.php.net/note/delete/83776/spam Del: non-english -- https://master.php.net/note/delete/83776/non-english Del: in docs -- https://master.php.net/note/delete/83776/in+docs Del: other reasons-- https://master.php.net/note/delete/83776 Reject -- https://master.php.net/note/reject/83776 Search -- https://master.php.net/manage/user-notes.php