note 86328 added to function.preg-quote

To bizzigul at hotmail dot fr: It's not a good practice to make somthing work *almost* all of the time. If the input contains a '`' you will still get an error. I recommend using the default delimiter ('/') and also feed this to preg_quote as second argument. ---- Server IP: 83.137.20.135 Probable Submitter: 87.213.210.124 ---- Manual Page -- http://www.php.net/manual/en/function.preg-quote.php Edit -- https://master.php.net/note/edit/86328 Del: integrated -- https://master.php.net/note/delete/86328/integrated Del: useless -- https://master.php.net/note/delete/86328/useless Del: bad code -- https://master.php.net/note/delete/86328/bad+code Del: spam -- https://master.php.net/note/delete/86328/spam Del: non-english -- https://master.php.net/note/delete/86328/non-english Del: in docs -- https://master.php.net/note/delete/86328/in+docs Del: other reasons-- https://master.php.net/note/delete/86328 Reject -- https://master.php.net/note/reject/86328 Search -- https://master.php.net/manage/user-notes.php