note 87213 deleted from function.eval by danbrown

Note Submitter: geek dot de at gmail dot com ---- in response to samme at vimio and warning for all using <?php eval('?'.'>'. $variable .'<'.'?php'); ?> In my version of PHP at least (5.2.5 windows), this just wouldn't work because you have to add another ' ' (space) after the php opening tag, as such: <?php eval('?'.'>'. $variable .'<'.'?php '); ?> It took me the better part of this afternoon to figure this out. So be warned! It seems like this is because the next php statement after that is appended resulting in something like: ? >hello world< ?phpdie('asd');