note 76064 deleted from function.is-array by danbrown

Note Submitter: elliot dot winkler at gmail dot com ---- @ markus-rehrs at gmx dot de: I don't see anywhere that $k is compared to $v -- it's compared to $next. In any case, you're right that there's an error -- but it's that $k == $next will be true if $next is 0 and $k is "0", or $next is 1 and $k is "1", etc. So yeah, it's probably better to use !== rather than !=. OTOH, this is really only a problem if you give your arrays ambiguously number-like string key names like "0", "1", etc.