note 87863 added to functions.arguments

Something that the documentation doesn't make clear is that you don't need to initialize a variable before passing it to a function that will treat it as an reference. Example <?php function foo(&$arg) { $arg = "whaha"; } foo($anUndefinedVar); // using an undefined var is perfectly valid, echo $anUndefinedVar; // you don't get an undefined variable error // output: whaha ?> You see? I didn't declare that $anUndefinedVar anywhere. ---- Server IP: 83.137.20.135 Probable Submitter: 83.247.70.113 ---- Manual Page -- http://www.php.net/manual/en/functions.arguments.php Edit -- https://master.php.net/note/edit/87863 Del: integrated -- https://master.php.net/note/delete/87863/integrated Del: useless -- https://master.php.net/note/delete/87863/useless Del: bad code -- https://master.php.net/note/delete/87863/bad+code Del: spam -- https://master.php.net/note/delete/87863/spam Del: non-english -- https://master.php.net/note/delete/87863/non-english Del: in docs -- https://master.php.net/note/delete/87863/in+docs Del: other reasons-- https://master.php.net/note/delete/87863 Reject -- https://master.php.net/note/reject/87863 Search -- https://master.php.net/manage/user-notes.php