note 25263 modified in control-structures.foreach by danbrown

"Also note that foreach operates on a copy of the specified array, not the array itself, therefore the array pointer is not modified as with the each() construct and changes to the array element returned are not reflected in the original array." In other words, this will work (not too expected): <?php foreach ($array as $array) { // ... } ?> While this won't: <?php while (list(, $array) = each($array)) { // ... } ?> --was-- "Also note that foreach operates on a copy of the specified array, not the array itself, therefore the array pointer is not modified as with the each() construct and changes to the array element returned are not reflected in the original array." In other words, this will work (not too expected): foreach ($array as $array) { // ... } While this won't: while (list(, $array) = each($array)) { // ... } http://php.net/manual/en/control-structures.foreach.php