note 79911 deleted from function.date by danbrown

Note Submitter: june at overlie dot no ---- re: marius at svr dot ro to anyone using marius' function, it needs some minor fixes (look for a ---->) <?php //The function returns the no. of business days between two dates and it skeeps the holidays function getWorkingDays($startDate,$endDate,$holidays){ //The total number of days between the two dates. We compute the no. of seconds and divide it to 60*60*24 //We add one to inlude both dates in the interval. $days = (strtotime($endDate) - strtotime($startDate)) / 86400 + 1; $no_full_weeks = floor($days / 7); $no_remaining_days = fmod($days, 7); //It will return 1 if it's Monday,.. ,7 for Sunday $the_first_day_of_week = date("N",strtotime($startDate)); $the_last_day_of_week = date("N",strtotime($endDate)); //---->The two can be equal in leap years when february has 29 days, the equal sign is added here //In the first case the whole interval is within a week, in the second case the interval falls in two weeks. if ($the_first_day_of_week <= $the_last_day_of_week){ if ($the_first_day_of_week <= 6 && 6 <= $the_last_day_of_week) $no_remaining_days--; if ($the_first_day_of_week <= 7 && 7 <= $the_last_day_of_week) $no_remaining_days--; } else{ if ($the_first_day_of_week <= 6) $no_remaining_days--; //In the case when the interval falls in two weeks, there will be a Sunday for sure $no_remaining_days--; } //The no. of business days is: (number of weeks between the two dates) * (5 working days) + the remainder //---->february in none leap years gave a remainder of 0 but still calculated weekends between first and last day, this is one way to fix it $workingDays = $no_full_weeks * 5; if ($no_remaining_days > 0 ) { $workingDays += $no_remaining_days; } //We subtract the holidays foreach($holidays as $holiday){ $time_stamp=strtotime($holiday); //If the holiday doesn't fall in weekend if (strtotime($startDate) <= $time_stamp && $time_stamp <= strtotime($endDate) && date("N",$time_stamp) != 6 && date("N",$time_stamp) != 7) $workingDays--; } return $workingDays; } //Example: $holidays=array("2006-12-25","2006-12-26","2007-01-01"); echo getWorkingDays("2006-12-22","2007-01-06",$holidays) // => will return 8 ?> Otherwise, I found this very useful, thanks marius:)