note 79367 deleted from function.strtotime by danbrown

Note Submitter: Hayley Watson ---- Beat's analysis fails to take into account the fact that when strtotime() subtracts three months it really does subtract three months: 31 December minus three months is 31 September. And a look at the calendar will show what "31 September" is really called. In other words strtotime() is doing exactly what Beat claims in the following note mktime() does. The reason why Beat's "workaround" works is because mktime( 23, 59, 59, 1 - 3, 0, 2008 ); represents the 0th day of the -2nd month of 2008. That's 0 October 2007. And 0 October is 30 September. Which is the reason Beat clearly discovered that using mktime( 23, 59, 59, 12 - 3, 31, 2007 ) to represent 31 December 2007 turned out not to work. mktime(23, 59, 59, 12, 31, 2007) == mktime(23, 59, 59, 1, 0, 2008) but mktime(23, 59, 59, 12-3, 31, 2007) refers to "31 September 2007", --> "1 October 2007"; and mktime(23, 59, 59, 1-3, 0, 2008) refers to "0 '-2' 2008" --> "0 October 2007" --> "30 September 2007". Just because the date you're starting from happens to be the last day of the month, it doesn't mean that subtracting a month will leave you at the last day of the previous month.