note 62702 deleted from language.types.null by danbrown
| From: | danbrown@php.net | Date: | Tue, 19 May 2009 14:20:09 +0000 |
| Subject: | note 62702 deleted from language.types.null by danbrown | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-155736@lists.php.net to get a copy of this message | ||
Note Submitter: owk dot ch199_ph at gadz dot org
----
To zola at zolaweb dot com :
"It treats NULL as the constant and unsets the variable."
It doesn't. As you are trying to find if your variable is empty, your code should be :
if (empty ($array['var'])) {
$array['var'] = "NULL";
}
You know, when "!isset ($var)" is true, $var is already not set...
PS : when "$var = '';", $var is set AND is equal to '', the empty
string.