note 91536 modified in function.str-replace by danbrown
| From: | danbrown@php.net | Date: | Tue, 16 Jun 2009 13:44:43 +0000 |
| Subject: | note 91536 modified in function.str-replace by danbrown | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-156917@lists.php.net to get a copy of this message | ||
Be careful when replacing characters (or repeated patterns in the FROM and TO arrays):
For example:
<?php
$arrFrom = array("1","2","3","B");
$arrTo = array("A","B","C","D");
$word = "ZBB2";
echo str_replace($arrFrom, $arrTo, $word);
?>
I would expect as result: "ZDDB"
However, this return: "ZDDD"
(Because B = D according to our array)
To make this work, use "strtr" instead:
<?php
$arr = array("1" => "A","2" => "B","3" =>
"C","B" => "D");
$word = "ZBB2";
echo strtr($word,$arr);
?>
This returns: "ZDDB"
--was--
Be careful when replacing characters (or repeated patterns in the FROM and TO arrays):
For example:
$arrFrom = array("1","2","3","B");
$arrTo = array("A","B","C","D");
$word = "ZBB2";
echo str_replace($arrFrom, $arrTo, $word);
I would expect as result: "ZDDB"
However, this return: "ZDDD"
(Because B = D according to our array)
To make this work, use "strtr" instead:
$arr = array("1" => "A","2" => "B","3" =>
"C","B" => "D");
$word = "ZBB2";
echo strtr($word,$arr);
This returns: "ZDDB"
http://php.net/manual/en/function.str-replace.php