note 93007 modified in function.date by danbrown

I couldn't find a function to do this properly. All functions I could find would use the current month as an argument. Anyway, this function will find the occurence of a particular weekday in a particular month. For instance, the second wednesday in june 2009 would be called by: <?php echo findFirstDayofWeek(6,2009, "Wednesday", 2); ?> Where 6 is "June", 2009 is the year, Wednesday is the weekday we want and 2 is the 2nd occurence. <?php function findFirstDayOfWeek($month, $year, $day, $offset){ // supply the month, year, day and offset $FirstDay = mktime(0, 0, 0, $month, 1, $year); // Get the first day of the month in question $DayName = date("l", $FirstDay); //set the name of the first day for the while loop $CurrentStamp = $FirstDay; // set a disposable variable for use in the while loop $Results = 0; //set the number of results (for use with the offset argument) While($Results != $offset){ //while the number of results does not equal the offset we are looking for $CurrentStamp = $CurrentStamp + 86400; // add a day if(date("l", $CurrentStamp) == $day){ // if the name of the weekday we are currently looping at is the same name as the argument supplied, set the date variable to that weekday and increment the results variable by 1 $Date = date("Y-m-d", $CurrentStamp); $Results++; } } if(date("n", $CurrentStamp) != $month){ // this line checks whether or not the date that the while loop has found is in the same month we are asking form otherwise, there must be no "3rd friday in august" return "No weekday at this offset"; } else { return $Date; //send back the date } } echo findFirstDayofWeek(9,2009, "Friday", 5); // returns a formatted date for the first instance of a certain day in the argumental month ?> --was-- I couldn't find a function to do this properly. All functions I could find would use the current month as an argument. Anyway, this function will find the occurence of a particular weekday in a particular month. For instance, the second wednesday in june 2009 would be called by: <? echo findFirstDayofWeek(6,2009, "Wednesday", 2); ?> Where 6 is "June", 2009 is the year, Wednesday is the weekday we want and 2 is the 2nd occurence. <? function findFirstDayOfWeek($month, $year, $day, $offset){ // supply the month, year, day and offset $FirstDay = mktime(0, 0, 0, $month, 1, $year); // Get the first day of the month in question $DayName = date("l", $FirstDay); //set the name of the first day for the while loop $CurrentStamp = $FirstDay; // set a disposable variable for use in the while loop $Results = 0; //set the number of results (for use with the offset argument) While($Results != $offset){ //while the number of results does not equal the offset we are looking for $CurrentStamp = $CurrentStamp + 86400; // add a day if(date("l", $CurrentStamp) == $day){ // if the name of the weekday we are currently looping at is the same name as the argument supplied, set the date variable to that weekday and increment the results variable by 1 $Date = date("Y-m-d", $CurrentStamp); $Results++; } } if(date("n", $CurrentStamp) != $month){ // this line checks whether or not the date that the while loop has found is in the same month we are asking form otherwise, there must be no "3rd friday in august" return "No weekday at this offset"; } else { return $Date; //send back the date } } echo findFirstDayofWeek(9,2009, "Friday", 5); // returns a formatted date for the first instance of a certain day in the argumental month ?> http://php.net/manual/en/function.date.php