note 88892 deleted from function.array-diff by danbrown

From: Date: Thu, 10 Sep 2009 00:57:02 +0000
Subject: note 88892 deleted from function.array-diff by danbrown
References: 1  Groups: php.notes 
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Note Submitter: ottodenn at gmail dot com ---- I needed a function which compares $arr1 with $arr2 and return all values from $arr2 that aren't in $arr1. Additionally the function has to compares multiarrays to. Here is it: <?php function arr_diff($a1,$a2){ $ar = array(); foreach ($a2 as $k => $v) { if (!is_array($v)) { if ($v !== $a1[$k]) $ar[$k] = $v; }else{ if ($arr = arr_diff($a1[$k], $a2[$k])) $ar[$k] = $arr; } } return $ar; } // example: $arr1 = array( 'user1' => array( 'name' => 'john d.', 'street' => 'elmstreet no. 2', 'city' => 'berlin' ), 'user2' => array( 'name' => 'harald c.', 'street' => 'b-street no. 7', 'city' => 'cologne' ) ); $arr2 = array( 'user1' => array( 'name' => 'john b.', // change #1 'street' => 'elmstreet no. 2', 'city' => 'berlin' ), 'user2' => array( 'name' => 'harald c.', 'street' => 'b-street no. 7', 'city' => 'bavaria' // change #2 ) ); print_r(arr_diff($arr1, $arr2)); /* will output: Array ( [user1] => Array ( [name] => john b. ) [user2] => Array ( [city] => bavaria ) ) */ ?> maybe someone can need this, for my usage it works proper. regards

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