note 84946 deleted from function.str-replace by philip

Note Submitter: max at efoxdesigns dot com ---- I'm sorry. I can't believe it: I messed up again. Something that I forgot is that the php empty() function considers the number zero (0) as an empty value. Therefore, we need to change our if statement to the following: <?php if ($i[0] !== null) $subject .= $replace[$i[0]]; ?> If we left it how it was, the replace ignores the first element of the arrays. ($array[0]) The reason that I used !empty() before, is that I wasn't sure what array_keys() returns if the element is not found (null? and empty string?), since both null and the empty string print out the same and I couldn't find what it returned in this case, in the manual. The final, working function would look like: <?php function str_replace_once($search, $replace, $subject) { $newArr = str_split($subject); $subject = ''; foreach ($newArr as $nchar) { $i = array_keys($search, $nchar); if ($i[0] !== null) $subject .= $replace[$i[0]]; else $subject .= $nchar; } return $subject; } ?>