note 93983 modified in function.parse-url by danbrown

Hello, for some odd reason, parse_url returns the host (ex. example.com) as the path when no scheme is provided in the input url. So I've written a quick function to get the real host: <?php function getHost($Address) { $parseUrl = parse_url(trim($Address)); return trim($parseUrl[host] ? $parseUrl[host] : array_shift(explode('/', $parseUrl[path], 2))); } getHost("example.com"); // Gives example.com getHost("http://example.com"); // Gives example.com getHost("www.example.com"); // Gives www.example.com getHost("http://example.com/xyz"); // Gives example.com ?> You could try anything! It gives the host (including the subdomain if exists). Hope it helped you. --was-- Hello, for some odd reason, parse_url returns the host (ex. google.com) as the path when no scheme is provided in the input url. So I've written a quick function to get the real host: <?php function getHost($Address) { $parseUrl = parse_url(trim($Address)); return trim($parseUrl[host] ? $parseUrl[host] : array_shift(explode('/', $parseUrl[path], 2))); } getHost("google.com"); // Gives google.com getHost("http://google.com"); // Gives google.com getHost("www.google.com"); // Gives www.google.com getHost("http://google.com/xyz"); // Gives google.com ?> You could try anything! It gives the host (including the subdomain if exists). Hope it helped you. http://php.net/manual/en/function.parse-url.php