note 95841 deleted from language.references.whatare by thiago
| From: | thiago@php.net | Date: | Mon, 25 Jan 2010 11:48:26 +0000 |
| Subject: | note 95841 deleted from language.references.whatare by thiago | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-165269@lists.php.net to get a copy of this message | ||
Note Submitter: zhangjyr at hotmail dot com
----
I actually write a test to approve what you can do with reference. Note that when you assign a
variable with an object, you don't change reference at all.
function & return_by_ref(&$out, $type) {
switch ($type) {
case 0:
$var = array("d"=>5);
$out = $var;
$var['d'] = 3;
return $var; // out? yes, out !== var
case 1:
$var = array("d"=>5);
$out = &$var;
$var['d'] = 3;
return $var; // out? no, out !== var
case 2:
$var = new stdClass();
$var->d = 5;
$out = $var;
$var->d = 3;
return $var; // out? yes, out === var
case 3:
$var = new stdClass();
$var->d = 5;
$out = &$var;
$var->d = 3;
return $var; // out? no, out !== var
default:
$out = new stdClass();
return $out; // out? yes, out === var
}
}
foreach
(array("array","array_reassign","obj","obj_reassign") as
$key => $name) {
$out = null;
$var = & $this->return_by_ref($out, $key);
echo "$name test:</br>";
echo "Is out evaluated:". var_export(isset($out), true) . "</br>";
echo "Is var and out identical:". var_export($var === $out, true) .
"</br>";
unset($out);
unset($var);