note 97097 added to function.array-splice

Splicing with NULL as replacement may result in unexpected behavior too. Typecasting NULL into an array results in an empty array (as "(array)NULL" equals "array()"). That means, instead of creating an element with value NULL just no new element ist created (just as if there was no replacement specified). If you want the splicing to create a new element with value NULL you have to use "array(NULL)" instead of NULL. You should expect this if you read the explanation carefully, but just as objects are considered as a special case for replacement, NULL should be too. The explanation of replacement better should read: "If replacement is just one element it is not necessary to put array() around it, unless the element is an array itself, an object or NULL." And the note better should be: "If replacement is not an array, it will be typecast to one (i.e. (array) $parameter). This may result in unexpected behavior when using an object or NULL replacement." jmtc ---- Server IP: 217.160.235.204 Probable Submitter: 80.153.162.95 ---- Manual Page -- http://www.php.net/manual/en/function.array-splice.php Edit -- https://master.php.net/note/edit/97097 Del: integrated -- https://master.php.net/note/delete/97097/integrated Del: useless -- https://master.php.net/note/delete/97097/useless Del: bad code -- https://master.php.net/note/delete/97097/bad+code Del: spam -- https://master.php.net/note/delete/97097/spam Del: non-english -- https://master.php.net/note/delete/97097/non-english Del: in docs -- https://master.php.net/note/delete/97097/in+docs Del: other reasons-- https://master.php.net/note/delete/97097 Reject -- https://master.php.net/note/reject/97097 Search -- https://master.php.net/manage/user-notes.php