note 101583 added to function.intval

The behaviour of intval() is interesting when supplying a base, and you better check your intval base-based expressions, as it is counter-intuitive. As the example shows <?php intval('42', 8); // => 34 intval(42, 8); // => 42 ! ?> PHP considers the 42 as being already an integer, and doesn't apply any conversion. And supplying <?php intval(49, 8); // => 49 ! ?> produces no error and no warning. ---- Server IP: 69.147.83.197 Probable Submitter: 110.5.47.62 ---- Manual Page -- http://www.php.net/manual/en/function.intval.php Edit -- https://master.php.net/note/edit/101583 Del: integrated -- https://master.php.net/note/delete/101583/integrated Del: useless -- https://master.php.net/note/delete/101583/useless Del: bad code -- https://master.php.net/note/delete/101583/bad+code Del: spam -- https://master.php.net/note/delete/101583/spam Del: non-english -- https://master.php.net/note/delete/101583/non-english Del: in docs -- https://master.php.net/note/delete/101583/in+docs Del: other reasons-- https://master.php.net/note/delete/101583 Reject -- https://master.php.net/note/reject/101583 Search -- https://master.php.net/manage/user-notes.php