note 102236 deleted from function.date-diff by danbrown

From: Date: Thu, 03 Feb 2011 14:48:05 +0000
Subject: note 102236 deleted from function.date-diff by danbrown
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Note Submitter: alessandro dot faustini at nixylab dot it ---- In versions < 5.3.0 Why do not simply use this form for calculate the number of days ? $today = strtotime("2011-02-03 00:00:00"); $myBirthDate = strtotime("1964-10-30 00:00:00"); printf("I'm %d days old.", round(abs($today-$myBirthDate)/60/60/24));

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