note 102339 deleted from function.mysql-fetch-field by danbrown

From: Date: Wed, 09 Feb 2011 16:54:11 +0000
Subject: note 102339 deleted from function.mysql-fetch-field by danbrown
References: 1  Groups: php.notes 
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Note Submitter: liveonaware [at] gmail dhat com ---- <?php /* Convert your Table fields / columns to variables and use them in your input tags to search the same Table... Just copy & paste code to see for yourself */ //1. connect to database $conn = mysql_connect('localhost', 'mysql_user', 'mysql_password'); if (!$conn) { die('Could not connect: ' . mysql_error()); } mysql_select_db('database'); //2. get all table fields in MySQL and store them in an array $table_fields = array(); $query = "SHOW COLUMNS FROM customers "; $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $table_fields[] = $row["Field"]; } ?> <form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post"> <table> <?php //3. make table fields to input tags inside a form foreach($table_fields as $field_input) { ?> <tr><td><?php echo $field_input.": "; ?></td><td><input type="text" name="<?php echo $field_input; ?>" /></td></tr> <?php } ?> <tr><td></td><td><input type="submit" name="submit" value="Go" style="width: 100px" /></td></tr> </table> </form> <?php //4. finally, search the same table if(isset($_POST["submit"])) { $query2 = "SELECT * FROM customers WHERE id IS NOT NULL "; //exclude the SUBMIT KEY on the POST Array, add as necessary //note: MySQL Text Blob, cannot be searched in my kind of Query below because of LIKE % so I added it in excluded list $excluded_keys_from_post = array('submit', 'sometextarea'); foreach($_POST as $key => $value) { if(in_array($key, $excluded_keys_from_post)) { //don't search the POST KEYS in the exclusion array continue; } $query2 .= " AND $key LIKE '" .mysql_real_escape_string($value). "%' "; } echo "<hr />"; $result2 = mysql_query($query2); echo $query2; //just to show what the query looks like while($row2 = mysql_fetch_array($result2)) { echo $row2["last_name"]."<br />"; } $numrows = mysql_num_rows($result2); if($numrows <= 0) { echo "No results found."; } } ?>

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