note 102988 added to language.operators.type

If you want to test if a classname is an instance of a class, the instanceof operator won't work. <?php $classname = 'MyClass'; if( $classname instanceof MyParentClass) echo 'Child of it'; else echo 'Not child of it'; ?> Will always output Not child of it You must use a ReflectionClass : <?php $classname = 'MyClass'; $myReflection = new ReflectionClass($classname); if( $myReflection->isSubclassOf('MyParentClass')) echo 'Child of it'; else echo 'Not child of it'; ?> Will output the good result. If you're testing an interface, use implementsInterface() instead of isSublassOf(). ---- Server IP: 195.221.21.36 Probable Submitter: 82.127.98.176 ---- Manual Page -- http://www.php.net/manual/en/language.operators.type.php Edit -- https://master.php.net/note/edit/102988 Del: integrated -- https://master.php.net/note/delete/102988/integrated Del: useless -- https://master.php.net/note/delete/102988/useless Del: bad code -- https://master.php.net/note/delete/102988/bad+code Del: spam -- https://master.php.net/note/delete/102988/spam Del: non-english -- https://master.php.net/note/delete/102988/non-english Del: in docs -- https://master.php.net/note/delete/102988/in+docs Del: other reasons-- https://master.php.net/note/delete/102988 Reject -- https://master.php.net/note/reject/102988 Search -- https://master.php.net/manage/user-notes.php