note 104374 added to language.types.null

Since there's no way to pass an undefined variable to a function, this construct foo($bar="quz") { print $bar; } will only work when called something like this if (!$bar) foo(); else foo($bar); (which stumped me .. ) ---- Server IP: 69.147.83.197 Probable Submitter: 92.254.50.195 ---- Manual Page -- http://www.php.net/manual/en/language.types.null.php Edit -- https://master.php.net/note/edit/104374 Del: integrated -- https://master.php.net/note/delete/104374/integrated Del: useless -- https://master.php.net/note/delete/104374/useless Del: bad code -- https://master.php.net/note/delete/104374/bad+code Del: spam -- https://master.php.net/note/delete/104374/spam Del: non-english -- https://master.php.net/note/delete/104374/non-english Del: in docs -- https://master.php.net/note/delete/104374/in+docs Del: other reasons-- https://master.php.net/note/delete/104374 Reject -- https://master.php.net/note/reject/104374 Search -- https://master.php.net/manage/user-notes.php