note 104426 added to function.escapeshellarg

If you don't want to rely on installed locales, you can use this instead of escapeshellarg fonction: $escapedArg = "'".str_replace("'", "'\\''", $arg)."'"; More details here : http://en.positon.org/post/PHP-escapeshellarg-function-UTF8-and-locales ---- Server IP: 89.31.146.176 Probable Submitter: 80.236.77.0 ---- Manual Page -- http://www.php.net/manual/en/function.escapeshellarg.php Edit -- https://master.php.net/note/edit/104426 Del: integrated -- https://master.php.net/note/delete/104426/integrated Del: useless -- https://master.php.net/note/delete/104426/useless Del: bad code -- https://master.php.net/note/delete/104426/bad+code Del: spam -- https://master.php.net/note/delete/104426/spam Del: non-english -- https://master.php.net/note/delete/104426/non-english Del: in docs -- https://master.php.net/note/delete/104426/in+docs Del: other reasons-- https://master.php.net/note/delete/104426 Reject -- https://master.php.net/note/reject/104426 Search -- https://master.php.net/manage/user-notes.php