note 105956 added to function.preg-replace

The instructions say, use \\\\ (four backslashes) to represent a backslash. You can shorthand this and use \\\ (three backslashes) to represent a backslash, because of the way the parsers read it. It appears the double escaping is required because the string is parsed twice, once by PHP and once by the regular expression generator. Thus it is expected that the PHP parser turns both instances above into \\ (two backslashes) for the PCRE parser. ---- Server IP: 69.147.83.197 Probable Submitter: 208.72.88.126 ---- Manual Page -- http://www.php.net/manual/en/function.preg-replace.php Edit -- https://master.php.net/note/edit/105956 Del: integrated -- https://master.php.net/note/delete/105956/integrated Del: useless -- https://master.php.net/note/delete/105956/useless Del: bad code -- https://master.php.net/note/delete/105956/bad+code Del: spam -- https://master.php.net/note/delete/105956/spam Del: non-english -- https://master.php.net/note/delete/105956/non-english Del: in docs -- https://master.php.net/note/delete/105956/in+docs Del: other reasons-- https://master.php.net/note/delete/105956 Reject -- https://master.php.net/note/reject/105956 Search -- https://master.php.net/manage/user-notes.php