note 100112 deleted from function.date by tularis

Note Submitter: jlathrop at horizonit dot us ---- Looking to output number of days left in the current year (and check if its a leap year - here it is) <?php $today = getdate(); // Get the current day in an array $yday = ($today['yday']); // Extract just the number of days since January 1st current year $leap = date('L'); // check if its a leap year $tdl = $leap + 365; // 365 days in an average year plus 1 day if its a leap year $dliy = $tdl - $yday; //Today number of days in the current year minus number of days since January 1st current year // Build the output using the above variables echo "As of today " . date('l F d, Y, ') . "We currently have " . $dliy . " days left in the year."; ?>