note 107520 deleted from regexp.reference.onlyonce by tularis

Note Submitter: Zeus ---- For what it's worth, here's the expression I came up with that (I think) matches everything the original does, and nothing else, while being efficient. ((?>[^\d<!?]+)|<((?>\d+)>)?|(?>[!?]+))*(?<=[!?]) It searches for any number of A: a series of anything besides a digit, <, !, or ?, and/or B: <, optionally followed by a series of digits and >, and/or C: one or more ? and/or ! . It then uses a look-behind to check that the end of the string is ! or ?. The series of digits, the series of (not-digit, not-<,!,?), and the series of ? and/or ! are all once-only. ((?>\D+)|<\d+>)*[!?] wouldn't work, because the once-only group could swallow up ! or ? at the end, and also the < that would start the alternate. The third group (?>[!?]+) is required in order to match the string when other characters (besides digits) follow the pattern. Example: aaaaa<123>!?!?!--- If the expression only needs to match a whole string, then the following will work. ^((?>[^\d<]+)|<((?>\d+)>)?)*(?<=[!?])$