note 16141 added to function.imagecreatefromjpeg
| From: | sondrobe at iespana dot es | Date: | Wed, 17 Oct 2001 15:59:10 +0000 |
| Subject: | note 16141 added to function.imagecreatefromjpeg | ||
| Groups: | php.notes | ||
| Request: | Send a blank email to php-notes+get-19048@lists.php.net to get a copy of this message | ||
i tried to use create a JPEG image with PHP function.. but said that function doesn't exist.. I
checked out vars on phpinfo() and i guess that gd version it's fine -1.6, with php 3.0.16-
this's that configuration
Configure command: ./configure '--with-apxs=/usr/sbin/apxs' '--prefix=/usr'
'--with-gd' '--with-zlib'
'--with-ttf=/usr/include/freetype/freetype.h'
'--enable-t1lib' '--with-xml' '--with-dbase'
'--with-filepro' '--with-config-file-path=/etc/httpd/conf'
'--with-fdftk=no' '--enable-debug=no'
'--enable-magic-quotes' '--enable-debugger' '--enable-bcmath'
'--enable-track-vars' '--enable-safe-mode' '--with-exec-dir=/usr/bin'
'--with-system-regex' '--with-ftp'
'--with-versioning' '--with-gdbm'
php3.ini file path is set to: /etc/httpd/conf
i don't know where to add --with-jpeg .. where should i do that?
thanks
--
http://www.php.net/manual/en/function.imagecreatefromjpeg.php
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