note 90859 deleted from function.list by googleguy

Note Submitter: claude dot pache at gmail dot com ---- A simple way to swap variables (correction of a note of mario dot mueller dot work at gmail dot com below): <?php list($var1, $var2) = array($var2, $var1); // swaps the values of $var1 and $var2 ?> Note that this is not equivalent to: <?php $var2 = $var1; $var1 = $var2; // $var1 and $var2 get both the old value of $var1 ?> as one could fear. Indeed, the array is constructed with the values of $var1 and $var2 (and not with the variables $var1 and $var2 themselves) before the assignment is carried out. Similarly, it is possible to bypass the problem pointed by sasha in the previous note by providing an expression rather than a variable on the right-hand side of the assignment operator: <?php $var = array ("test" ,"blah"); list ($a,$var) = $var + array(); echo $a ; // prints "test", not "b" echo $var ; // prints "blah" ?>